Energy Engineering - Meccanica dei Solidi

Homework 3 e 4

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v 2=300"¥ 8 . 21 สิส + 557054.2867 +=102555 -=55557 -48 ==1551357.211 Jy -感喪 :Aiftai - to 」'- :Sun -2200 /75 -50.3 - 20/50 - # -sho /seag-int - 3 -noo/Bosc - = 1582999 . 958 + 189908 . 3487+1157234 , 984+224214 . 52 = 3154357 , 784MomentocentrifugioJay = Andandyn + AzdxaYe ....- 2200 . As-5ong)(r-c2ol +roofus-5oss(50 _ 120p+2uo(n-50 . 39)(45-u202f 100138-50 . 31)(30-42af =- 199982 - &u- H2025-t0-910olauetUFeFos=- 224S!·GERmmYAssiprincipaliDinerzia=- - 2.1- 22·5.38 /Age2a) = -25 eu5y11551057 .40- 3154357 . 78422 =⼀× 5 。 550α ーーヌ」⼦ポ Ju e JuJu = Juox = (x+ 5y + (x-5)2 = Jx = 2194985 / 4 JJu = [min-EE-K-Jep = 1520727 , 500Jx * VerificadiLJu = Jxcast1ay-25xyCes(a)sin() + JyeinasClcaloMx *e My * α ⼆ーコ」コポ Mr *= Mxcosta) + Mywinko = -832455.43NmumMy *= Myus(a) + Mxsin(a) = 1533797 . 33UmmCodeG /On e Cray ⼤*世 22 , 30 µo Y *= 42 . 02 m_ -=- Ribass _ หร 42.02 = -23-11MPo1520729.583σan- U * ⼗* 153327→ - 3322.39 =10.75Mor3194985 . 4 ‰ 90300 = 17.92Mianboao